Saturday 3 November 2012

Question 6

Q.6 Take a neutron star with 2Msun but a radius of 10Km! What is the accelaration of gravity at the surface of it? how much greater than g(9.8) is it? Finally how much will you weigh on it?(assume you somehow dont turn into a puddle of protoplasm)?

Ans:

          sun mass = 1.98x10^30
          m = 2 x 1.98x10^30 = 3.96x10^30 Kg
          radius = 10 Km
          G = 6.67x10^-11 N/Kg^2
          m2 = my weight = 40Kg (assuming)
          g = 9.8 m/s^2
          
          formula = (G x m)/r^2
                  = (6.67x10^-11 x 3.96x10^30) / 10^2
                  =  2.64132xx10^18 km/s^2
so:

          Gravity = 2.64x10^18 km/s^2
          g = 9.8 m/s^2
    
          times greater = gravity/g
                        = 2.64x10^18 / 9.8
                        = 2.69x10^17 times   g         
I would weigh:

          m2 = 40 Kg
          F = m x gravity 
            = 40 x 2.64x10^18
            = 1.055x10^20 Kg !!!!!!!!!!!!!! 

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