Orbital Decay from Gravitational Radiation:
(Note: Remember those folds forming in the graph in Part one? Well those showed continuity...No strange effect in that...)
In part 2 we will use Power Radiated, which we found in Part one to find the rate of decrease of Orbit Radius with respect to time. In other words we will find $\frac{dr}{dt}$, the derivative or rate of change.
The formula for finding this stuff is
.
The orbit decays at a rate proportional to the inverse third power of the radius.
The variables are same as in part 1.
Well Im going to take $r=1.5*10^{11}m$ and $m2=6*10^{24}kg$ and $m1$ is our variable from $2*10^{29} \text{ to } 3*10^{30}kg $:
A similar graph like in part 1. The unit for orbital decay is m/s. Earth with our sun is $1.1*10^{-20}m/s$ .
Now lets take our 2 solar mass Neutron stars and plot their orbit decay with Radius as our variable:
(Note: Remember those folds forming in the graph in Part one? Well those showed continuity...No strange effect in that...)
In part 2 we will use Power Radiated, which we found in Part one to find the rate of decrease of Orbit Radius with respect to time. In other words we will find $\frac{dr}{dt}$, the derivative or rate of change.
The formula for finding this stuff is
.The orbit decays at a rate proportional to the inverse third power of the radius.
The variables are same as in part 1.
Well Im going to take $r=1.5*10^{11}m$ and $m2=6*10^{24}kg$ and $m1$ is our variable from $2*10^{29} \text{ to } 3*10^{30}kg $:
Now lets take our 2 solar mass Neutron stars and plot their orbit decay with Radius as our variable:
So as the orbit radius decreases the decay increases exponentially.
Now for 3D:
We are going to only take our Neutron star case as graphs are similar.
So with relation to $m1,m2$ the graph is:
and for $m1,r$:
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