Find the roche limit of a planet with Mass $5.87*10^28Kg$ (Heehee! I love to exaggerate some things!) and me with a mass of $45Kg$. My radius is about 13cm or 0.00013km! The Formula is this for a rigid object 
Ans:
$M_M = 5.87*10^28Kg$
$M_m = 45Kg$
$R_m = 0.00013km$
$d = 2.44*R_m(\frac{M_M}{M_m})^\frac{1}{3}$
$d = 2.44*0.00013*(\frac{5.87*10^28}{45})^(\frac{1}{3})$
$d = 346583.8921\text{km or} 3.465*10^5 km$ #at this distance I will be the planets ring!
New question:
A supermassive star with density $7005.5Kg/m^2$ and a planets density of $1000Kg/m^2$ and $R = 47008Km$. The planet is liquidy, find the roche limit with the formula
Ans:
$p_M = 7005.5kg.m^2$
$p_m = 1000kg/m^2$
$R = 47008Km$
$d = 2.44 * R(\frac{p_M}{p_m})^(\frac{1}{3})$
$d = 2.44 * 47008(\frac{7005.5}{1000})^(frac{1}{3})$
$d = 219469.7Km = 2.19*10^5km$
Ans:
$M_M = 5.87*10^28Kg$
$M_m = 45Kg$
$R_m = 0.00013km$
$d = 2.44*R_m(\frac{M_M}{M_m})^\frac{1}{3}$
$d = 2.44*0.00013*(\frac{5.87*10^28}{45})^(\frac{1}{3})$
$d = 346583.8921\text{km or} 3.465*10^5 km$ #at this distance I will be the planets ring!
New question:
A supermassive star with density $7005.5Kg/m^2$ and a planets density of $1000Kg/m^2$ and $R = 47008Km$. The planet is liquidy, find the roche limit with the formula
Ans:
$p_M = 7005.5kg.m^2$
$p_m = 1000kg/m^2$
$R = 47008Km$
$d = 2.44 * R(\frac{p_M}{p_m})^(\frac{1}{3})$
$d = 2.44 * 47008(\frac{7005.5}{1000})^(frac{1}{3})$
$d = 219469.7Km = 2.19*10^5km$
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