Find the roche limit of a planet with Mass 5.87*10^28Kg (Heehee! I love to exaggerate some things!) and me with a mass of 45Kg. My radius is about 13cm or 0.00013km! The Formula is this for a rigid object 
Ans:
M_M = 5.87*10^28Kg
M_m = 45Kg
R_m = 0.00013km
d = 2.44*R_m(\frac{M_M}{M_m})^\frac{1}{3}
d = 2.44*0.00013*(\frac{5.87*10^28}{45})^(\frac{1}{3})
d = 346583.8921\text{km or} 3.465*10^5 km #at this distance I will be the planets ring!
New question:
A supermassive star with density 7005.5Kg/m^2 and a planets density of 1000Kg/m^2 and R = 47008Km. The planet is liquidy, find the roche limit with the formula
Ans:
p_M = 7005.5kg.m^2
p_m = 1000kg/m^2
R = 47008Km
d = 2.44 * R(\frac{p_M}{p_m})^(\frac{1}{3})
d = 2.44 * 47008(\frac{7005.5}{1000})^(frac{1}{3})
d = 219469.7Km = 2.19*10^5km

Ans:
M_M = 5.87*10^28Kg
M_m = 45Kg
R_m = 0.00013km
d = 2.44*R_m(\frac{M_M}{M_m})^\frac{1}{3}
d = 2.44*0.00013*(\frac{5.87*10^28}{45})^(\frac{1}{3})
d = 346583.8921\text{km or} 3.465*10^5 km #at this distance I will be the planets ring!
New question:
A supermassive star with density 7005.5Kg/m^2 and a planets density of 1000Kg/m^2 and R = 47008Km. The planet is liquidy, find the roche limit with the formula

Ans:
p_M = 7005.5kg.m^2
p_m = 1000kg/m^2
R = 47008Km
d = 2.44 * R(\frac{p_M}{p_m})^(\frac{1}{3})
d = 2.44 * 47008(\frac{7005.5}{1000})^(frac{1}{3})
d = 219469.7Km = 2.19*10^5km
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